Phy que 17 repost pls answer

Solution:

R e s o n a n c e f r e q u e n c y ω_{0} = \sqrt{ω_{1} ω_{2}} H e r e ω_{0} = 12 o r 144 = ω_{1} ω_{2} A l s o ω_{1} + ω_{2} = 25 W e k n o w t h a t {(ω_{1} - ω_{2})}^{2} = {(ω_{1} + ω_{2})}^{2} - 4 ω_{1} ω_{2} S o {(ω_{1} - ω_{2})}^{2} = {(25)}^{2} - 4 \times 144 o r {(ω_{1} - ω_{2})}^{2} = 625 - 576 o r {(ω_{1} - ω_{2})}^{2} = 49 o r ω_{1} - ω_{2} = 7 (i n S I u n i t) H e r t z = \frac{r a d / s e c}{0.15} s o ω_{1} - ω_{2} (r a d / s e c) = 7 \times 0.15 = 1.05