Solution: Calculating the force mdvdt =mg−i/B0 Also, vB0I=Ldidt md2vdt2 =−B0l⋅didt ∴ md2vdt2 = -B02I2vL ⇒ d2vdt2+B02l2mL ⋅v=0 This is the equation of SHM⇒ω= B0lmL= 2×912×8 ⇒ω=9rad/s

Phy que 4.

Solution:

Calculating the force

m \frac{d v}{d t} ​ = m g - i / B_{0} A l s o, v B_{0} I = L \frac{d i}{d t} m \frac{d^{2} v}{d t^{2}} ​ = - B_{0} l \cdot \frac{d i}{d t} ∴ m \frac{d^{2} v}{d t^{2}} = - \frac{B_{0}^{2} I^{2} v}{L} \Rightarrow \frac{d^{2} v}{d t^{2}} + \frac{B_{0}^{2} l^{2}}{m L} \cdot v = 0 T h i s i s t h e e q u a t i o n o f S H M \Rightarrow ω = \frac{B_{0} l}{\sqrt{m L}} = \frac{2 \times 9}{\sqrt{\frac{1}{2} \times 8}} \Rightarrow ω = 9 r a d / s

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