# Pl slove this

From given information we form our diagram , As  :

Here , we know

AP  =  BP  =  $\frac{1}{2}$AB
And
BQ  =  CQ  =  $\frac{1}{2}$BC
And
AR  =  CR  =  $\frac{1}{2}$AC

And

APQR is a parallelogram

And from converse of mid-point theorem we know if we join mid point of two sides , that the joining line is parallel to the third line .

Here we get $∆$ ABC , $∆$ PBQ and $∆$ RQC are similar to each other .

So , we get

So, we can say that

Area of parallelogram APQR is $\frac{1}{2}$ of the $∆$ ABC( answer)
Regards

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