Please help me in solving question 9 Share with your friends Share 0 Gursheen Kaur answered this Dear Student, Solution) arc AXB=12×arc BYC⇒∠AOB=12∠BOCAOC is the diameter.∴∠AOB+∠BOC=180°⇒12∠BOC+∠BOC=180°⇒32∠BOC=180°⇒∠BOC=23×180°=120° Regards! 1 View Full Answer
