Please help me to solve Q 3
Dear Student,
Volume of the wooden cube
= 10 x 10 x 10 = 1000 cm3
When the cubic block floats, the volume of water displaced by the submerged part
= 10 x 10 x (10-3)
= 700 cm3
Mass of this water
= V x d
= 700 x 1 => 700 g
As the cubic block is floating,
Weight of the displaced water = Weight of the block
Hence, density of the block = Mass /Volume
= 700/ 1000
= 0.7 g/cm-3
So, density of water = 1 g/cm3
So, Part of cube submerged in water,
= density of body/density of water
= 0.7/1
= 7/10
Part of the cube above water = 1 - 7/10
= 3/10
Hence, 3 cm of cube is above the water.
Regards