Please please someone help me
Dear Student,
Distance travelled by the body from O to C = Area under the S-T graph.
Area of square, ABED = side2 = AB2 = 6 x 6 = 36 m
Area of triangle, ADO = 1/2 × h × b = 1/2 × 6 × 4 = 12 m
Area of triangle, BEC = 1/2 × 6 × 6 = 18 m
Total distance = Area of square + area of both triangles
= 12 + 36 + 18
= 66 m
Regards
Distance travelled by the body from O to C = Area under the S-T graph.
Area of square, ABED = side2 = AB2 = 6 x 6 = 36 m
Area of triangle, ADO = 1/2 × h × b = 1/2 × 6 × 4 = 12 m
Area of triangle, BEC = 1/2 × 6 × 6 = 18 m
Total distance = Area of square + area of both triangles
= 12 + 36 + 18
= 66 m
Regards