Please solve ques no-15 Share with your friends Share 0 Yash Ranjan Mishra answered this Dear student We have, ABCD as the given parallelogram.Since, ABCD is a ∥gm, thenDC∥AB and DA∥CB.Now, AB is produced to point F such that AF is a straight line.Now, DC∥AF as, DC∥AB.Since, DC∥AF and CB is a transversal, then∠ECD = ∠EBF Alternate interior anglesIn ∆ECD and ∆EBF∠ECD = ∠EBF Proved above EC = EB As, E is the mid point of BC∠CED = ∠BEF Vertically opposite angles⇒∆ECD ≅ ∆EBF ASA⇒DC = BF CPCTNow, DC = AB Opposite sides of ∥gm are equalSo, we get AB = BFHence, AF = AB + BF⇒AF = AB + AB as, BF = AB⇒AF = 2AB Regards 0 View Full Answer Vyomm Vaidya answered this i am in class 7 1
