# Please solve question no 8 and 9

The following is solution to Q8.

Angle C of right angled triangle ABC is the right angle.

Hence, side AB is the hypotenuse.

As per Pythagoras Theorem,

$A{B}^{2}=A{C}^{2}+C{B}^{2}\phantom{\rule{0ex}{0ex}}AB=13cmandAC=5cm\phantom{\rule{0ex}{0ex}}Thus,\phantom{\rule{0ex}{0ex}}{13}^{2}={5}^{2}+C{B}^{2}\phantom{\rule{0ex}{0ex}}i.eC{B}^{2}=169-25=144\phantom{\rule{0ex}{0ex}}i.eCB=12cm(Takingpositivesquareroot\mathrm{sin}celengthcannotbenegative)\phantom{\rule{0ex}{0ex}}$

Kindly post the remaining questions on a separate thread so that our experts can provide with some meaningful help.

Regards.

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