Please solve this.....

Dear Student.

We have: y=x2+k1x-21we know (3,0) is on the graph of the polynomial.Putting x=3, y=0, we get:0=9+k1×3-213k1=12k1=4So, we get the polynomial: y=x2+4x-21Now, putting x=k2 and y=00=k22+4k2-21k22+7k2-3k2-21=0k2(k2+7)-3(k2+7)=0(k2-3)(k2+7)=0So, k2=3 and k2=-7k2=3 is already given on the graphs, so k2=-7
We hope that this answer solves your query.
Regards. 

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-7 may be
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yes -7 is ans I am sure it's help u
Than you this only
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