P l e a s e   a n s w e r I f   a + c b   a n d   1 a + 1 c + 1 a - b + 1 c - b = 0   t h e n   1 a , 1 b , 1 c   a r e   i n   ( 1 ) A . P . ( 2 ) G . P . ( 3 ) H . P . ( 4 ) n o n e   o f   t h e s e

Dear Student,


1a+1c+1a-b+1c-b=01a+1c-b+1c+1a-b=0c-b+aac-b+a-b+cca-b=0a-b+c×1ac-b+1ca-b=0since a+cbhence a+c-b0therefore 1ac-b+1ca-b=0ca-cb+ac-abac×c-b×a-b=0ca-cb+ac-ab=02ac-bc-ab=02ac=ab+bc2b=1a+1cHence 1a,1b,1c are in AP
Regards,

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