Solution:6 tan-25π3tan (-A)=-tan Atan-25π3=-tan25π3=-tan24π+π3=-tan8π+π3tan(nπ+A)=tan A-tan8π+π3=-tanπ3=-3

Plz do 6

Solution : 6 . \tan (\frac{- 25 π}{3}) \tan (- A) = - \tan A \tan (\frac{- 25 π}{3}) = - \tan (\frac{25 π}{3}) = - \tan (\frac{24 π + π}{3}) = - \tan (8 π + \frac{π}{3}) \tan (nπ + A) = \tan A - \tan (8 π + \frac{π}{3}) = - \tan (\frac{π}{3}) = - \sqrt{3}