Prove that 2 tan inverse (1/3) + cot inverse 4 = tan inverse (16/13)

LHS = 2 tan-113 + cot-14=tan-12×131 - 19 + tan-114=tan-12/38/9 + tan-114=tan-134 + tan-114=tan-13/4+1/41 - 34×14=tan-111-316=tan-11613=RHS

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