Prove that in a quadrilateral the __sum of all sides__ is greater than the sum of it's __ diagonals __.

oh sorry!

the correct solution is -

consider a quadrilateral ABCD where AC and BD are the diagonals

AB+BCis greater than AC .......1 (SUM OF TWO SIDES IS GREATER THAN THE THIRD SIDE)

AD+DCis greater thanAC..........2

AB+ADis greater thanBD ..........3

DC+BCis greater thanBD..........4

ADDING 1,2,3,4

AB+BC+AD+DC+AB+AD+DC+BCis grater than AC+AC+BD+BD

2(AB+BC+CD+DA)is greater than 2(AC+BD)

AB+BC+CD+DA is greater than AC+BC

hence proved

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