prove the question Share with your friends Share 0 Neha Sethi answered this Dear student sinα cosβ+cosα sinβ2+cosα cosβ-sinα sinβ2=sinα+β2+cosα+β2=1Note:1) sinA+B=sinA cosB+cosA sinB2) cos(A+B)=cosA cosB-sinA sinB3) sin2A+cos2A=1 Regards 0 View Full Answer