prove the question

Dear student
sinα cosβ+cosα sinβ2+cosα cosβ-sinα sinβ2=sinα+β2+cosα+β2=1Note:1) sinA+B=sinA cosB+cosA sinB2) cos(A+B)=cosA cosB-sinA sinB3) sin2A+cos2A=1
Regards

  • 0
What are you looking for?