Q . 1 + x a 1 + x x + a 1 a 1 a 2 + . . . . . . . + x x + a 1 x + a 2 . . . . . x + a n - 1 a 1 a 2 . . . . . . . a n = 1 . x + a 1 x + a 2 . . . . x + a n a 1 a 2 . . . . a n 2 . x - a 1 x - a 2 . . . . x - a n a 1 a 2 . . . . a n 3 . x + a 1 x + a 2 . . . . x + a n 4 . x - a 1 x - a 2 . . . . x - a n Share with your friends Share 0 Anuradha Sharma answered this Hi, Since it is objective type question so we have to use the option to get the answer as it also involes PMI. Now let Px= 1+xa1+xx+a1a1a2+......+xx+a1x+a2.....x+an-1a1a2....anat x = 0 P0=1now from the options c, d clearly ruled out. now from option a, = a1a2....ana1a2....an= 1 =P0and from option b =-1na1a2....ana1a2....an= -1n so here condition arouses so option a is clear answer -1 View Full Answer