Q. Evaluate : 3 sin 3 A + 2 cos 5 A + 10 ° 3 tan 3 A - cos e c 5 A - 20 ° , when A = 10 ° . Share with your friends Share 0 Abhishek Jha answered this Dear Student, Here is the solution of your asked query: 3 sin 3A+2 cos 5A+103 tan 3A-cosec5A-20=3 sin 30+2 cos50+103 tan 30-cosec50-20 {putting A=10°}=312+2 cos 603 13-cosec 30=32+221-2=5-2=-52 ANS... Regards 5 View Full Answer Abhishek answered this Proved -3 Rahul Sharma answered this I hope Every thing is clear. If any doubt in any subject, then ask me any time or any questions. 2 Ahmad answered this answer 2