Q=If f(x)=sin4x +cos2x/sin2x +cos4x for xbelonging to R,then f(2002) will be equal to?
f(x) = sin4 x + cos2 x / sin2 x + cos4 x
= (1 - cos2 x)2 + cos2 x /sin2 x + cos4 x
= 1 + cos4 x - 2 cos2 x + cos2 x / sin2 x + cos4 x
= 1 + cos4 x - cos2 x / sin2 x + cos4 x
= sin2 x + cos4 x / sin2 x + cos4 x
= 1
hence f(2002) = 1