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Q. If three coins are tossed simultaneously, then find the probability of getting at least two heads. 

Dear Student,

 When 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.
 Total number of possible outcomes = 8

    Let E be the event of getting at least two heads.
    Then, the favourable outcomes are HHH, HHT, THH, and HTH.
    ​Number of favourable outcomes = 4
  ∴ P(getting at least 2 heads) = Number of favourable outcomesTotal number of possible outcomes =48  = 12
Regards

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Total number of outcomes=8
outcomes are=H H H
                        H H T
                         H T H
                         T H H
                         T T T
                          T T H
                         T H T
                         H T T
NUMBER OF FAVOURABLE OUTCOMES ARE=4
SO PROBABLITY=4/8=1/2
                          
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