Question no 10 10 If cos θ = 12, find sec2 θ + tan2 θ7-2 - Maths - Some Applications of Trigonometry

Question

Question no 10

10       I f   cos   θ   =
  1 2 ,   f i n d   s e c 2   θ   +
  tan 2   θ 7 - 2   s e c   θ
  ·   cos e c   θ

Sanjari Kalantri · Accepted Answer

Dear Student,

cosθ = 12 = cos60° ⇒ θ = 60°Then, sec2θ + tan2θ7 - 2secθcosecθ= sec260° + tan260°7 - 2sec60°cosec60°= 22 + 327 - 2223= 4 + 37 - 83= 773 - 83= 7373 - 8

Question no 10 10 . I f cos θ = 1 2 , f i n d s e c 2 θ + tan 2 θ 7 - 2 s e c θ · cos e c θ

Question no 10

$10 . I f \cos θ = \frac{1}{2}, f i n d \frac{s e c^{2} θ + \tan^{2} θ}{7 - 2 s e c θ \cdot \cos e c θ}$