Dear student,a=k; b=2; c=3; p=3; q=6; r=10if ap≠bqthen the system will have unique solutionSo, k3≠26k≠3×26k≠1Regards

Question No: 2

Dear student, a = k; b = 2; c = 3; p = 3; q = 6; r = 10 if \frac{a}{p} \neq \frac{b}{q} then the system will have unique solution So, \frac{k}{3} \neq \frac{2}{6} k \neq \frac{3 \times 2}{6} k \neq 1 Regards

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