Dear student,a1=4; b1=6; c1=7; a2=12; b2=18; c2=21a1a2=412=13; b1b2=618=13; c1c2=721=13As, a1a2=b1b2=c1c2So, the eqn has infinitely many solution Regards

Question No: 3

Dear student, a_{1} = 4; b_{1} = 6; c_{1} = 7; a_{2} = 12; b_{^{2}} = 18; c_{2} = 21 \frac{a_{1}}{a_{2}} = \frac{4}{12} = \frac{1}{3}; \frac{b_{1}}{b_{2}} = \frac{6}{18} = \frac{1}{3}; \frac{c_{1}}{c_{2}} = \frac{7}{21} = \frac{1}{3} As, \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}} So, the eqn . has infinitely many solution . Regards

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