respected sir/madam

given below is the frequency distribution of wages of 30 workers

wages

110-130

130-150

150-170

170-190

190-210

210-230

230-250

No. Of workers

3

4

5

6

5

4

3

a worker is selected at random. find the probability that his wages are:

1. at least Rs.150

2. at most Rs.190

???

pls. answer fast

wagesfrequencycumulative frequency
110-13033
130-15047
150-170512
170-190618
190-210523
210-230427
230-250330
 total = 30 

total number of workers = 30

the number of workers , whose wages are less than 150 = 7

therefore the probability that the his wages is less than 150 = 7/30

therefore the probability that his wages is at least 150 = 1- 7/30 = 23/30

the wages is at most 190, the number of workers whose wages are less than or equal to 190 = 18

therefore the required probability = 18/30 = 3/5

hope this helps you.

cheers!!

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