# Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm × 20 cm × 5 cm and the smaller of dimensions 15 cm × 12 cm × 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs 4 for 1000 cm2, find the cost of cardboard required for supplying 250 boxes of each kind. Plz solve this

the dimension of bigger box is 25×20×5.

the outer surface area =2(25×20+20×5+5×25)=1450 cm square

the area of extra sheet = 5% of 1450=

the total area of cardboard required for bigger box =1450+72.5=1522.5 cm square

the dimension of smaller box is 15×12×5.

the outer surface area =2(15×12+12×5+5×15)=630 cm square

the area of extra sheet = 5% of 630=

the total area of cardboard required for bigger box =630+31.5=661.5 cm square

for 250 boxes of each kind  required cardboard = 250*(1522.5+661.5)=250*2184 =546000cm square

cost of the card board=

• 36

for bigger box

l=25   b=20 h=5

total surface area of the bigger box

2(lb+bh+lh)

2(25)(20)+(20)(5)+(25)(5) = 1450cm^3

2

• -10

Length (l1) of bigger box = 25 cm

Breadth (b1) of bigger box = 20 cm

Height (h1) of bigger box = 5 cm

Total surface area of bigger box = 2(lb lh + bh)

= [2(25 × 20 + 25 × 5 + 20 × 5)] cm2

= [2(500 + 125 + 100)] cm2

= 1450 cm2

Extra area required for overlapping

= 72.5 cm2

While considering all overlaps, total surface area of 1 bigger box

= (1450 + 72.5) cm2 =1522.5 cm2

Area of cardboard sheet required for 250 such bigger boxes

= (1522.5 × 250) cm2 = 380625 cm2

Similarly, total surface area of smaller box = [2(15 ×12 + 15 × 5 + 12 × 5] cm2

= [2(180 + 75 + 60)] cm2

= (2 × 315) cm2

= 630 cm2

Therefore, extra area required for overlappingcm2

Total surface area of 1 smaller box while considering all overlaps

= (630 + 31.5) cm2 = 661.5 cm2

Area of cardboard sheet required for 250 smaller boxes = (250 × 661.5) cm2

= 165375 cm2

Total cardboard sheet required = (380625 + 165375) cm2

= 546000 cm2

Cost of 1000 cm2 cardboard sheet = Rs 4

Cost of 546000 cm2 cardboard sheet

Therefore, the cost of cardboard sheet required for 250 such boxes of each kind will be Rs 2184.

• 2

Length (l1) of bigger box = 25 cm

Breadth (b1) of bigger box = 20 cm

Height (h1) of bigger box = 5 cm

Total surface area of bigger box = 2(lb lh + bh)

= [2(25 × 20 + 25 × 5 + 20 × 5)] cm2

= [2(500 + 125 + 100)] cm2

= 1450 cm2

Extra area required for overlapping

= 72.5 cm2

While considering all overlaps, total surface area of 1 bigger box

= (1450 + 72.5) cm2 =1522.5 cm2

Area of cardboard sheet required for 250 such bigger boxes

= (1522.5 × 250) cm2 = 380625 cm2

Similarly, total surface area of smaller box = [2(15 ×12 + 15 × 5 + 12 × 5] cm2

= [2(180 + 75 + 60)] cm2

= (2 × 315) cm2

= 630 cm2

Therefore, extra area required for overlappingcm2

Total surface area of 1 smaller box while considering all overlaps

= (630 + 31.5) cm2 = 661.5 cm2

Area of cardboard sheet required for 250 smaller boxes = (250 × 661.5) cm2

= 165375 cm2

Total cardboard sheet required = (380625 + 165375) cm2

= 546000 cm2

Cost of 1000 cm2 cardboard sheet = Rs 4

Cost of 546000 cm2 cardboard sheet

Therefore, the cost of cardboard sheet required for 250 such boxes of each kind will be Rs 2184.

• 3
What are you looking for?