Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets Two sizes of boxes - Maths - Surface Areas and Volumes

Question

Shanti Sweets Stall was placing an order for making cardboard
boxes for packing their sweets Two sizes of boxes were required The
bigger of dimensions 25 cm × 20 cm × 5 cm and the
smaller of dimensions 15 cm × 12 cm × 5 cm For all the
overlaps, 5% of the total surface area is required extra If the
cost of the cardboard is Rs 4 for 1000 cm2, find the
cost of cardboard required for supplying 250 boxes of each kind Plz
solve this

Ajanta Trivedi · Accepted Answer

the dimension of bigger box is 25Ã—20Ã—5 the outer surface area =2(25Ã—20+20Ã—5+5Ã—25)=1450 cm square the area of extra sheet = 5% of 1450= $1450 * \frac{5}{100} = 72 5 c m^{2}$ the total area of cardboard required for bigger box =1450+72 5=1522 5 cm square the dimension of smaller box is 15Ã—12Ã—5 the outer surface area =2(15Ã—12+12Ã—5+5Ã—15)=630 cm square the area of extra sheet = 5% of 630= $630 * \frac{5}{100} = 31 5 c m^{2}$ the total area of cardboard required for bigger box =630+31 5=661 5 cm square for 250 boxes of each kind required cardboard = 250*(1522 5+661 5)=250*2184 =546000cm square cost of the card board= $546000 * \frac{4}{1000} = 546 * 4 = 2184 R s$