Show that square of any positive odd integer is of the form 8m + 1, for some integer m.
by euclids divison lemma for any 2 positive integers a and b there exits a unique interger q and r such that a=bq+r ,, 0 is < or equal to r is greater than b
the possible values of r may be0,1,2,3,4,5,6,7.
if r=0 then a=8q+0
here 8q2 is m
if r=1 then a=8m+1
=64q2 + 16q+1
here m= 8q2+2q