solve 3x+2y=11,2x+3y=4 by graphical method
We have,
3x + 2y = 11
and,
2x + 3y = 4

Since both the lines intersect at (5,-2).
So, (5,-2) is the solution.
3x + 2y = 11
x | y |
0 | 11/2 |
11/3 | 0 |
and,
2x + 3y = 4
x | y |
0 | 4/3 |
2 | 0 |

Since both the lines intersect at (5,-2).
So, (5,-2) is the solution.