Solve this : 8. Kinetic energy of electron in a mono electronic species is 312 KJ/mole. Then which of the following statements are correct. (a) The electron is present in 2nd orbit of He+ ion. (b) The electron is present in the 2nd orbit of H- atom (c) The electron is present in the 3rd orbit of Li+2 in . (d) The electron is present in the fourth orbit of He+ ion. Share with your friends Share 6 Bharti Paliwal answered this Dear StudentKintic energy = K z e22rwhere, K= 9*109 Nm2C-2 z= atomic number of the specie e = 1.6*10-19 CThus, 312*103 = 9*109 * z2* (1.6*10-19)2 * r⇒312*103 * 29*109 * (1.6*10-19) = z2r⇒ z2r = 4.310-14⇒ zr = 2.0710-14 thus, Z=2 which is atomic no. for HeThen the correct statements are (a) and (d).Regards -11 View Full Answer