Solve this :

8. Kinetic energy of electron in a mono electronic species is 312 KJ/mole. Then which of the following statements are correct.
(a) The electron is present in 2nd orbit of He+ ion.
(b) The electron is present in the 2nd orbit of H- atom
(c) The electron is present in the 3rd orbit of Li+2 in .
(d) The electron is present in the fourth orbit of He+ ion.
 

Dear StudentKintic energy = K z e22rwhere, K= 9*109 Nm2C-2              z= atomic number of the specie              e = 1.6*10-19 CThus, 312*103 = 9*109 * z2* (1.6*10-19)2 * r312*103 * 29*109 * (1.6*10-19) = z2r z2r = 4.310-14 zr = 2.0710-14 thus, Z=2 which is atomic no. for HeThen the correct statements are (a) and (d).Regards

  • -11
What are you looking for?