Solve this :
A person standing between two vertical cliffs and 640 m away from the nearest cliff shouted. He  heard the first echo after 4 seconds and the second echo 3 seconds later. Calculate.
(a) the velocity of sound in air, and
(b) the distance between the cliffs

Dear student,

(i) Velocity of the sound v=2dtv=2×6404=320m/s(ii) Distance between the two cliffsv=2x't, total time is 7 secor 320=2x'7x'=1120mDistance between the two cliffsso x =1120+640=1760m


  • 0
What are you looking for?