Solve this:

Q.  The synthesis of ammonia is done by Haber's process. The reaction involved during the synthesis of ammonia (NH3) is 
N2 (g)+3H​2(g)  2NH3(g)

How many litres of NH3 will be produced at STP from 20 moles of N2? ​
(A) 696 L
(B) 796 L
(C) 896 L
(D) 996 L

Dear Student,

Please find below the solution of your asked query:

Haber's process- 

N2 + 3H2 → 2NH3

Number of moles of N2=  1 
Number of moles of H2 =3
Number of moles of NH3=  2

Thus, 1 mole of nitrogen reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia.

So, 20 moles of nitrogen reacts with 60 moles of hydrogen gas to produce 40 moles of ammonia.


And as we know that,

1 mole of ammonia gas at STP = 22.4 L volume of ammonia gas

So, 40 moles of ammonia gas at STP = 40 * 22.4 L volume of ammonia gas

                                                           = 896 L of ammonia gas

Therefore, option (C) is correct.

Hope this information clears your doubts about the topic.

Keep asking!!

Regards

  • 0
Imol of N2=2mol of NH3.
SO, 20 mole of N2 PRODUCE 40 MOLE OF NH3 .
NO. OF MOLES = VOLUME OF NH3 / STP .
40 X 22.7 = VOLUME OF NH3.
=896L
  • 1
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