Solve this:
Q. The synthesis of ammonia is done by Haber's process. The reaction involved during the synthesis of ammonia (NH3) is
N2 (g)+3H2(g) 2NH3(g)
How many litres of NH3 will be produced at STP from 20 moles of N2?
(A) 696 L
(B) 796 L
(C) 896 L
(D) 996 L
Dear Student,
Please find below the solution of your asked query:
Haber's process-
N2 + 3H2 → 2NH3
Number of moles of N2= 1
Number of moles of H2 =3
Number of moles of NH3= 2
Thus, 1 mole of nitrogen reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia.
So, 20 moles of nitrogen reacts with 60 moles of hydrogen gas to produce 40 moles of ammonia.
And as we know that,
1 mole of ammonia gas at STP = 22.4 L volume of ammonia gas
So, 40 moles of ammonia gas at STP = 40 * 22.4 L volume of ammonia gas
= 896 L of ammonia gas
Therefore, option (C) is correct.
Hope this information clears your doubts about the topic.
Keep asking!!
Regards
Please find below the solution of your asked query:
Haber's process-
N2 + 3H2 → 2NH3
Number of moles of N2= 1
Number of moles of H2 =3
Number of moles of NH3= 2
Thus, 1 mole of nitrogen reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia.
So, 20 moles of nitrogen reacts with 60 moles of hydrogen gas to produce 40 moles of ammonia.
And as we know that,
1 mole of ammonia gas at STP = 22.4 L volume of ammonia gas
So, 40 moles of ammonia gas at STP = 40 * 22.4 L volume of ammonia gas
= 896 L of ammonia gas
Therefore, option (C) is correct.
Hope this information clears your doubts about the topic.
Keep asking!!
Regards