Dear Student Resistance of wire R can be given as R =ρlASoR1=ρ2lA/2=4RR2=ρl/22A=R4SoR1R2 =4RR4 =161 â€‹â€‹â€‹ Regards

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Dear Student

$R e s i s \tan c e o f w i r e R c a n b e g i v e n a s R = \frac{ρ l}{A} S o R_{1} = \frac{ρ 2 l}{A / 2} = 4 R R_{2} = \frac{ρ l / 2}{2 A} = \frac{R}{4} S o \frac{R_{1}}{R_{2}} = \frac{4 R}{\frac{R}{4}} = \frac{16}{1}$

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