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Dear Student,

Due to time constraints it is not possible to solve the entire question paper.

Please find below the solution for some of the queries


$$\begin{gathered} Question 12 \\ apply formula for amount \\ A=P{\left[1-\frac{R}{100}\right]}^T \\ A=25000\times {\left[1-\frac{5}{100}\right]}^1 \\ \Rightarrow 25000\times \frac{95}{100} \\ =250\times 95 \\ =23750 \\ Question 13) \\ P=625 \\ R=4\% \\ time T=2 years \\ A=P{\left[1+\frac{R}{100}\right]}^T \\ A=625\times {\left[1+\frac{4}{100}\right]}^2 \\ =625\times {\left[\frac{26}{25}\right]}^2 \\ =625\times \frac{676}{625} \\ =676 \\ CI=A-P \\ Hence CI=676-625 \\ =51 \\ SI=\frac{PRT}{100} \\ =\frac{625\times 4\times 2}{100} \\ =50 \\ Difference in CI and SI \\ =CI-SI \\ =51-50 \\ =1 \\ Hence there is difference of 1 rupees between CI and SI \end{gathered}$$

For answers to rest of the queries kindly post in separate thread

Regards,