tan(1/2(cos^-1(square root 5/3))

Tan(½cos-1(√5/3))
Let (½cos-1(√5/3)=x
cos-1(√5/3)=2x
(√5/3)=cos 2x
(√5/3)=1-tan2x/1+tan2x
√5 +√5tan2x= 3- 3tan2x
√5tan2x + 3tan2x= 3 - √5
= 3 + √5(tan2x)= 3 - √5
Tan2x = 3 - √5/ 3 + √5
On rationalising we get
Tan2x =( 3 - √5)2/9-5
Tan2x =( 3 - √5)2/4
Tan x =( 3 - √5)/2
 x =tan-1( 3 - √5)/2
now Tan(½cos-1(√5/3))
=tan x
=tan(tan-1( 3 - √5)/2)
= ( 3 - √5)/2=ans
Hope u liked it J
  • 151
ans = (3-root5)/2
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=(3-root5)/2
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Thnx
  • -13
This is right answer (3-√5)/2

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ANS = ?
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thanx for this wonderful answer eshika arya
  • -3
सब को छोड़ो मेरी सुनो This is right answer

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Thanks for the answer provided it really helped me.
  • -5
This is correct 🔥☺️☺️

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