The 7th term of an AP. is 32 and its 13th term is 62. Find the progression.

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Hii Nishant
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a7=32 and a13= 62

We can write 7th term ( a7) as -

a7=a+6d
32=a+6d ---- equation 1

Similarly -

a13=a+12d
62= a+12d ------ equation 2

Using elimination method , subtracting equation 2 and 1 ,

U will get -

d=5 and substituting this value of d in equation 1 -

32= a+6?5
32=a+30

Therefore -
a =2

Now you can form you arithmetic progression if you know your first term and the common difference ---

AP: 2 , 7 , 12 , 17 ,..........

Hope it will help you.. Do tell me..

By the way from which school you are ? Please let me know.
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Nishant I gave you the solution to your question.. Please see to it...
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