The difference of the squares of two natural numbers is 84. The square of the larger part is 25 times the smaller part. Find the numbers

By the first condition,
x ²+y²=84  ---- (i)
By the second condition,
x²=25y   ------(ii)
So,
by substituting (ii) in (i),
25y-y²=84
y²-25y+84 =0
y²-21y-4y+84=0
y(y-21)-4(y-21)=0

y-21=0
y=21

OR

y-4=0
y=4
 

Answer is 21 and 4

This my ans....

4/2?,and100/2?

Solution :-
Let x and y are two natural number
A.T.Q.
X?-y? = 84 ........(i)
X?=25y? ...(ii)
Putting the value of x?in equation (i)
25y?-y?=84
24y?=84
Y=?7/2 .Ans
Putting the value of in equation (ii)
X?=25*7/2
X=5?7/2 .Ans.

Solution :-
Let larger number = X and smaller number= Y
A.T.Q.
X?-y?=84 .....(i)
X?=25y ....(ii)
Putting the value of x?in equation (i)
25y-y?=84
0=Y?-25y+84
0=Y?-21y-4y+84
0=Y(y-21)-4(y-21)
0=(Y-21)(y-4)

Y-21=0 and Y-4=0
Y=21 and Y=4

First,we take the value of y=21 in equation (ii)
X?=25*21
X=?525
Secondly, we take the value of y=4 in equation (ii)
X?=25*4
X?=100
X=10
So,on putting the values of x and y in equation (i)
The answer come x=10 and y=4.

3 x square 2 minus x minus 4 batao answer