the distance travelled by a body falling freely from rest in 2nd 3rd and 5th second?? Answer is 3:5:9...I am in 10th class..I used the known formula s=1/2 gt^2 as u is o ..but answer is not coming ..there is another formula used but why don't this work to take out answer ??plzz explain as a student of class 10th

Dear student,
s=ut+12at2is the formula to calculate distanace travelled in total t secondwheras,to calculate distance travlled in nth sec can be calculated ass=u+a2(2n-1)


Regards,

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