# the distance travelled by a body falling freely from rest in 2nd 3rd and 5th second?? Answer is 3:5:9...I am in 10th class..I used the known formula s=1/2 gt^2 as u is o ..but answer is not coming ..there is another formula used but why don't this work to take out answer ??plzz explain as a student of class 10th

$s=ut+\frac{1}{2}a{t}^{2}\phantom{\rule{0ex}{0ex}}istheformulatocalculatedis\mathrm{tan}acetravelledintotaltsecond\phantom{\rule{0ex}{0ex}}wheras,\phantom{\rule{0ex}{0ex}}tocalculatedis\mathrm{tan}cetravlledin{n}^{th}seccanbecalculatedas\phantom{\rule{0ex}{0ex}}s=u+\frac{a}{2}(2n-1)$

Regards,

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