The equation of the chord of the ellipse 2x+ 5y= 20 bisected at the point (2,1) is :

a). 4x + 5y + 13 = 0
​b). 4x + 5y = 13
c). 5x+4y+13 = 0
d). 5x+4y = 13

Dear Student,
Please find below the solution to the asked query:

Equation of chord of ellipse x2a2+y2b2=1 having mid point x1,y1 isxx1a2+yy1b2=x1a2+y12b22x2+5y2=20x210+y24=1Hence equation of chord will be xx110+yy14=x1210+y124Given that x1,y1=2,12x10+y4=410+14x5+y4=25+144x+5y20=8+5204x+5y=13 Answer

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