The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

Length of the minute hand is 5cm.

Length of the minute hand is the Radius of the circular clock.

So r = 14cm

As the minute hand subtends 360? to cover 60 minutes.

Therefore,

Angle subtended by the minute hand in 1 minute = 360?/60? = 6?

So angle subtended by minute hand in 5 minutes is = 6 ? 5 = 30?

So we have angle subtended in 5 mins = 30?

Now,

Area swept in 5 minutes = Theta/360 ? ?r?

=> 30/360 ? 22/7 ? 14 ? 14

=> (22 ? 2 ? 14) / 12

=> 154 / 3

=> 51.33cm?

?Therefore area swept by the minute hand in 5 minutes = 51.33cm?

Length of the minute hand is the Radius of the circular clock.

So r = 14cm

As the minute hand subtends 360? to cover 60 minutes.

Therefore,

Angle subtended by the minute hand in 1 minute = 360?/60? = 6?

So angle subtended by minute hand in 5 minutes is = 6 ? 5 = 30?

So we have angle subtended in 5 mins = 30?

Now,

Area swept in 5 minutes = Theta/360 ? ?r?

=> 30/360 ? 22/7 ? 14 ? 14

=> (22 ? 2 ? 14) / 12

=> 154 / 3

=> 51.33cm?

?Therefore area swept by the minute hand in 5 minutes = 51.33cm?

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