The pair of linear equations 3x + 4y = 12 and y =4 has

a. no common solution b. infinetly many solutions c. unique solution d. none of these

Given, pair of equation are:

3x + 4y = 12 and y = 4

They can be rewritten as:

3x + 4y – 12 = 0  ...  (1)

and y = 4

Put y = 4 in (1), we get

 3x + 4 (4)  – 12 = 0

⇒ 3x – 4 = 0

So, the given system of equation will have unique solution for and y = 4.

  • 0

3x+4y=12                 y=4

3x+4[4]=12

3x+16=12       its no common solution option [a]

  • -1
What are you looking for?