the perimeter of a triangle is 30cm and the circumference of its incircle is 88cm . the area of the triangle
Given: Perimeter of ∆ABC = 30 cm
⇒AB + BC + AC = 30 cm ...... (1)
and circumference of incircle = 88 cm
⇒ 2π radius = 88 cm
Thus radius = OP = OQ = OR = 14 cm ........ (2)
we know that radius of circle is perpendicular to the tangent of the point of contact
⇒ OP ⊥ AB, OQ ⊥ BC, OR ⊥ AC
Now Area (∆ABC) = Area(AOB) + Area (BOC) + Area (AOC)