The spring has a force constant of 24N/m The mass of the block attached to the spring is 4 - Physics - Work Energy And Power

Question

The spring has a force constant of 24N/m The mass of the block
attached to the spring is 4 kg Initially the block is at rest and
spring is unstretched The horizontal surface is frictionless If a
constant horizontal force of 10N is applied on the block, then what
is the speed of the block when it has been moved through a distance
of 0 5 m?

Ved Prakash Lakhera · Accepted Answer

force constant of spring=24N/m
mass of the block=4Kg
horizontal force= 10N
 Therefore      when this force of 10N is pulling the mass 4Kgfollowing is the eqn of motion,         F-K x=m a    10-24×0
5=4×aor     4a=10-12or          a=-0
5m/s2
Here negative sign shows that acceleration of the spring is taking place in adirection opposite to that of a force acting
let ue pressume the block of mass 4Kg starts with initial velocity u=0and attains velocity v after travelling distance x=0
5m, therefore,             v2 = 0+2×0
5×0 5=2×0 25
or          v=0
5×2 = 0 5×1 4=0 7m/s