The work function of caesium is 2.14eV.find a)threshold frequency.b) the wavelength of incident light if the photocurrent is brought to zero by a stopping potential of 0.60v
a) $ = h * threshold frequency ( $ = work function )
2.14 * 1.6 * 10-19 = 6.6 * 10-34 * threshold frequency
threshold frequency = 2.14 * 1.6 * 10-19 / 6.6 * 10-34
= 5.2 * 1014 hertz .
b) 4.5*10-7 meter
