There are a total of 200 boys. 100 of the play cricket, 50 of them play hockey, 60 of them play basketball. 30 play both cricket and hockey. 35 play both hockey and basketball and 45 play both basketball and cricket.

Question:what is minimum no. of students playing all three games and how?

a)20 b)18 c)17

union = u

intersection = ^

now....

n( c u h u b) = 200

n ( c) = 100

n ( h) = 50

n (b) = 60

n (c ^ h) = 30

n (h ^ b) = 35

n (c ^ b) = 45

n( c u h u b) = n(c) + n(h) + n(b) - n(c^h) - n(h^b) - n(b^c) + n (c ^ b ^ h)

200 = 100 + 50 + 60 - 30 - 35 - 45 + n(c ^ b ^ h)

200 = 100 + n(c ^ b ^ h)

200 - 100 = n(c ^ b ^ h)

100 = n ( c ^ b ^ h) ans..

ACC. to ur ques. frnd ur options r wrng. i gave u the solution dude u can check it.....

bt i thnk m rght..

HOPE U GET IT...!!!!!

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