Three charges -15nC, +10nC and +10nC are placed at the corners A,B and C of an isolated triangle ABC with sides AB=AC=0.8m and BC=0.04m. Calculate the resultant potential at the midpoint of AC.

Dear Student,

I think it should be mid point of BC .

V=-k150.82+0.022+10k0.02+10k0.0210-90.82+0.0220.8V=9-150.8+100.02+100.02=8831.25 volt Regards

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