Triangle ABC is equilateral triangle.Cis the mid point of DE.AD is perpendicular to AC and BE is perpendicular to BC.Prove that triangle DAC is congruent to triangle EBC.Angle DAC and angle EBC are 90 degrees.

In ΔDAC and ΔEBC,

AC = BC (Sides of an equilateral triangle)

∠DAC = ∠EBC = 90° (Given)

CD = CE (C is the mid-point of side DE, Given)

By RHS congruency criteria

ΔDAC is congruent to ΔEBC.

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