Two blocks of masses 2 kg. and 1 kg. are in contact with each other on a frictionless table . When a horizontal force of 3 N is applied to the block of mass 2 kg. the value of the force of contact between the two block is :
(1) 4 N (2) 3N (3) 5 N (4) 1 N
The acceleration of the system is, a = 3/(2 + 1) = (3/3)=1 m/s2
The reaction force experienced by the blocks is equal to the force on 1 kg that makes it move with acceleration ‘a’ which is = 1 × 1 = 1 N