Two sides of an triangle are 88 m and 114 m .If perimeter is 320 m find its area Share with your friends Share 5 Vijay Kumar Gupta answered this The two sides of a triangle are 88 m and 114 m and the perimeteris 320 m.Let the sides be denoted by a, b and cThen, we have a+b+c=320 88+114+c=320 202+c=320 c=320-202 c=118 mThe semi perimeter 's' is given by, s= 3202 m=160 mThe area of the triangle is given by Heron's formula, Area of △=s s-a s-b s-c =160 160-88 160-114 160-118 =160 72 46 42 =2×2×2×2×2×5 2×2×2×3×3 2×23 2×21 =2×2×2×2×2×35×23×21 =962415 Thus the required area is 962415 m2 11 View Full Answer
