Using properties of sets prove the statements given:-
(i) For all sets A and B, AU(B-A) = AUB
(ii) For all sets A and B, A-(A-B) = AintersectionB
(iii) For all sets A and B, (AUB)-B = A-B
1)
To show that A u (B - A) = A U B we need to show two things:
1) A U (B - A) A U B.
2) A U B A U (B - A)
First, let x A U (B - A).
In the similar way should try for the other two for your own practice.
To show that A u (B - A) = A U B we need to show two things:
1) A U (B - A) A U B.
2) A U B A U (B - A)
First, let x A U (B - A).
In the similar way should try for the other two for your own practice.