Using the distance formula show that The points (4,3) (5,1) and (1,9) are collinear
Hi Ahamed dear, distance AB = √{(-1)^2 + (2)^2} = √5
Distance BC = √{(4)^2 + (-8)^2} = √80 = 4√5
Distance AC = √{3^2 +(-6)^2} = √45 = 3√5
It is vivid clear that BC = BA + AC
A, B and C are collinear with A lies in between B and C
Distance BC = √{(4)^2 + (-8)^2} = √80 = 4√5
Distance AC = √{3^2 +(-6)^2} = √45 = 3√5
It is vivid clear that BC = BA + AC
A, B and C are collinear with A lies in between B and C