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value of root3 cosec 60' - sec60' is

Please find below the solution to the asked query:

$\sqrt{3}\mathrm{cosec}\left(60\xb0\right)-\mathrm{sec}\left(60\xb0\right)\phantom{\rule{0ex}{0ex}}=\sqrt{3}\times \frac{2}{\sqrt{3}}-2\phantom{\rule{0ex}{0ex}}=2-2\phantom{\rule{0ex}{0ex}}=0$

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