What is the Probability that an ordinary year has 53 Sundays?
The number of days in an ordinary year = 365
The number of days in a week = 7
∴ Number of complete weeks in a year = 365 ÷ 7
On dividing 365 by 7, we obtain that there are 52 complete weeks in a year and 1 day is left as remainder.
Every week has 1 Sunday, so there must be 52 Sundays in a year.
Now, the remaining 1 day can be any one of the 7 days.
Hence, the probability for the remaining day of being Sunday =