W h i c h o f t h e f o l l o w i n g a b o u t S F 4 , S O F 4 , C H 2 S F 4 , O C F 2 m o l e c u l e s i s c o r r e c t ( A ) E q u a t i o n F S F b o n d a n g l e i n S O F 4 w i l l b e l e s s t h a n t h a t i n S F 4 m o l e c u l e ( B ) T h e t w o h y d r o g e n s c a r b o n s u l p h u r a n d t w o f l o u r i n e s ( o f a x i a l p o s i t i o n s ) i n m o l e c u l e C H 2 S F 4 ( C ) T h e b o n d a n g l e F C O w i l l b e < 120 ° i n m o l e c u l e O C F 2 ( D ) T h e a x i a l F S F b o n d a n g l e i n S F 4 = 180 ° Share with your friends Share 12 Geetha answered this a) Equatorial FSF bond angle in SOF4 > SF4b) In CH2SF4 molecule has all 6 atoms lie in the same plane - Correct statementc)SF4 and SOF4 shape is trigonal bipyramid structure. The lone pair repulsion is more than oxygen double bond and the axial FSF angle is less thanFSO - Wrong statementd) The axial FSF bond angle in SF4 ≠ 180Thus option B is correct statement 6 View Full Answer Chetan Bansal answered this i think option D is correct of question number 23 -4